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[单选题]
某居民客户抄见电量为W=1000(kWh),已发现空转30天。经测试闪烁一个脉冲所需时间为T=120(s),电能表常数为C=1600(imp/kWh),居民客户每日停电时间为t=16(h),电能表倍率为B=1,计算应退电量()kWh。
A.6
B.9
C.18
D.27
查看答案
![](https://static.youtibao.com/asksite/comm/h5/images/solist_ts.png)
A.6
B.9
C.18
D.27
A.5000
B.10000
C.15000
D.20000
A.95238kWh
B.105263kWh
C.1789474kWh
D.2000000kWh
A.10%
B.5%
C.2.5%
D.%
A.应追补电量为19500kWh
B.应退电量为19500kWh
C.应追补电量为15500kWh
D.应追退电量为16500kWh
A.665
B.1430
C.1330
D.715
A.1000
B.2000
C.3000
D.2200