已知圆C:x2+y2-2x+4y+1=0,那么与圆C有相同的圆心,且经过点(-2,2)的圆的方程是()
A.(x-1)2+(y+2)2=5
B.(x-1)2+(y+2)2=25
C.(x+1)2+(y-2)2=5
D.(x+1)2+(y-2)2=25
#include
void main0
int x=5;
switch(2*x-3) {
case 4: printf("%d "x);
case 7: printf("%d ",2*x+1);
case 10: printf("%d ",3*x-1); break;
default: printf("%s"," default/n");
}
}
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函数f(x)=x2+2x- 5,则f(x-1)等于() (A)x2-6 (B)x2-5 (C)x2-2x-6 (D)x2-2x-5
函数f(x)=(x-1)(x-3)的最小值是() (A)-4 (B)-3 (C)-1 (D)0