![](https://static.youtibao.com/asksite/comm/h5/images/m_q_title.png)
含有11.2 g KOH的稀溶液与1 L 0.1 mol·L-1的H2SO4溶液反应,放出11.46 kJ的热量,表示该反应的中和热的热化学方程式为()
A.KOH(aq)+1/2H2SO4(aq)===1/2K2SO4(aq)+H2O(l) ΔH=-11.46 kJ•mol-1
B.2KOH(aq)+H2SO4(aq)===K2SO4(aq)+2H2O(l) ΔH=-11.46 kJ·mol-1
C.2KOH(aq)+H2SO4(aq)===K2SO4(aq)+2H2O(l) ΔH=-114.6 kJ·mol-1
D.KOH(aq)+1/2H2SO4(aq)===1/2K2SO4(aq)+H2O(l) ΔH=-57.3 kJ•mol-1
![](https://static.youtibao.com/asksite/comm/h5/images/m_q_a.png)
D、KOH(aq)+1/2H2SO4(aq)===1/2K2SO4(aq)+H2O(l) ΔH=-57.3 kJ•mol-1
![](https://static.youtibao.com/asksite/comm/h5/images/solist_ts.png)